Why does the JK flip-flop toggles on the 'negative edge' of its clock input when its inputs are connected to +v (i.e when j=1 , k=1)? - Quora
![Solved) - For a negative edge-triggered J-K flip-flop with the inputs in... (1 Answer) | Transtutors Solved) - For a negative edge-triggered J-K flip-flop with the inputs in... (1 Answer) | Transtutors](https://files.transtutors.com/book/qimg/ff6d2c20-be2a-49b0-a13e-21ac47050a21.png)
Solved) - For a negative edge-triggered J-K flip-flop with the inputs in... (1 Answer) | Transtutors
![This happens to be a negative edge triggered JK flip flop. I used boolean algebra and found D = E' and E = D'. Given the propagation delay I thought this was This happens to be a negative edge triggered JK flip flop. I used boolean algebra and found D = E' and E = D'. Given the propagation delay I thought this was](https://i.redd.it/cv6hms38j8051.jpg)
This happens to be a negative edge triggered JK flip flop. I used boolean algebra and found D = E' and E = D'. Given the propagation delay I thought this was
![flipflop - JK flip-flop timing diagram positive edge triggering - Electrical Engineering Stack Exchange flipflop - JK flip-flop timing diagram positive edge triggering - Electrical Engineering Stack Exchange](https://i.stack.imgur.com/xUix0.png)